Answers

• kthorngren Posts: 21,341Questions: 26Answers: 4,954

  December 2020 edited December 2020 Answer ✓

  Your test case doesn't run. You need to define the variable table which you want to be an instance of the Datatables API. Like this:

      $('input:checkbox').on('change', function () {
          var table =  $('#table_id').DataTable();
          table.draw();
      });     
  

  Or you can do this on the line with your Datatable initialization like this example.

  Kevin
• 2008jackson Posts: 38Questions: 9Answers: 0

  December 2020

  Worked perfectly! Thankyou @kthorngren