FORM DATA ON PHP PAGE
FORM DATA ON PHP PAGE
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Hi everyone, when i try to send a form of a records inside this pagination, a php page read me just some records, and missed other...
But in a html page i have all a record list ..i missed something?
But in a html page i have all a record list ..i missed something?
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Replies
Allan
if i use this
[code]
var oTable;
$(document).ready(function() {
$('form').submit( function() {
var sData = $('input', oTable.fnGetNodes()).serialize();
alert( "The following data would have been submitted to the server: \n\n"+sData );
return false;
} );
oTable = $('.tabledata').dataTable();
} );
[/code]
that let me see aler of all my data, but now how send them? ..sorry im a newbe
[code]
var oTable;
$(document).ready(function() {
$('form').submit( function() {
var sData = $('input', oTable.fnGetNodes()).serialize();
$.post("test.php", sData);
alert("Data Loaded: " + sData);
//alert( "The following data would have been submitted to the server: \n\n"+sData );
return false;
} );
oTable = $('.tabledata').dataTable();
} );
[/code]
and yes page "test.php" is called but still not with sData value
[code]
var oTable;
$(document).ready(function() {
$('form').submit( function() {
var sData = $('input', oTable.fnGetNodes()).serialize();
var sDatas = $('select', oTable.fnGetNodes()).serialize();
var sCustomer = '<?php echo $_GET['view']?>';
$.post("test.php", {myinput: sData, myselect: sDatas, mycustomer: sCustomer});
return false;
} );
oTable = $('.tabledata').dataTable();
} );
[/code]