How to get filtered data without data of hidden columns

Oensel

Is there a simple way to get all displayed data (including the other pages) ?

That's how I get all filtered data:

   table.rows( { filter: 'applied' } ).data()

But the information of hidden columns is included and I don't want it.

I also need to get all headers title but only the visible, not the hidden ones.
Any ideas ?

Oensel

I solved the problem:

    var coulmnsVisible = tableApi.columns().visible();
    var columns = [];   
    var data = [];

    // Write all visible columns title to 'columns'
    $.each(tableApi.columns().header(),function(index)
    {
        if(coulmnsVisible [index])
        {
            columns.push($(this).text());
        }
    });

    // write all visible cells text to 'data'
    $.each(tableApi.rows( { filter: 'applied' } ).data(), function(rowIndex)
    {
        var columnIndex = 0;
        var cells = [];
        $.each(this, function(key,value)
        {
            if(coulmnsVisible [columnIndex++])
            {
                cells .push(value);
            }
        });
        data.push(cells .join('~~'));
    });