Can't Reinitialize DataTable Error

Can't Reinitialize DataTable Error

whichrtmejwhichrtmej Posts: 3Questions: 1Answers: 0

I am new to datatables, query and have been trying to load a datatable on the click of a button. I want my datatable to also have Alphabetical input search capabilities.

When I click on the button to load the table I get the following error: "DataTables warning: table id=example - Cannot reinitialize DataTable. For more information about this error, please see...."

When I click "OK" on the error my DataTable loads, looks and works as it should. I can't figure out how to get ride of the error. See my code below. Any help would be appreciated.

<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>Untitled Document</title>
<script type="text/javascript" language="javascript" src="https://code.jquery.com/jquery-3.3.1.js"></script>
<link href="css/bootstrap-4.0.0.css" rel="stylesheet">
<link rel="stylesheet" href="https://cdn.datatables.net/1.10.19/css/jquery.dataTables.min.css">
<script type="text/javascript" src="https://cdn.datatables.net/1.10.19/js/jquery.dataTables.min.js"></script>
<style>
div.alphabet {
    display: table;
    width: 90%;
    margin-bottom: 1em;
    margin-top: 1em;
}
 
div.alphabet span {
    display: table-cell;
    color: #3174c7;
    cursor: pointer;
    text-align: center;
    width: 3.5%
}
 
div.alphabet span:hover {
    text-decoration: underline;
}
 
div.alphabet span.active {
    color: black;
}
</style>
<script>
$(document).ready(function(){
  $("#btnShow").click(function(){
      if(! $.fn.DataTable.isDataTable( '#example' )){
        showTable();
      }
  });
});

function showTable(){
$('#example').css("display","");
  var table = $('#example').DataTable({
    "responsive": true,
    "ajax": "data/ticatsAllTimeRoster.txt"
}); 

  var table = $('#example').DataTable( {
    dom: 'Alfrtip'
} );
var _alphabetSearch = '';
 
$.fn.dataTable.ext.search.push( function ( settings, searchData ) {
    if ( ! _alphabetSearch ) {
        return true;
    }
 
    if ( searchData[0].charAt(0) === _alphabetSearch ) {
        return true;
    }
 
    return false;
} );

$(document).ready(function() {
    var table = $('#example').DataTable({
        retrieve: true
    });
 
    var alphabet = $('<div class="alphabet"/>').append( 'Search: ' );
 
    $('<span class="clear active"/>')
        .data( 'letter', '' )
        .html( 'None' )
        .appendTo( alphabet );
 
    for ( var i=0 ; i<26 ; i++ ) {
        var letter = String.fromCharCode( 65 + i );
 
        $('<span/>')
            .data( 'letter', letter )
            .html( letter )
            .appendTo( alphabet );
    }
 
    alphabet.insertBefore( table.table().container() );
 
    alphabet.on( 'click', 'span', function () {
        alphabet.find( '.active' ).removeClass( 'active' );
        $(this).addClass( 'active' );
 
        _alphabetSearch = $(this).data('letter');
        table.draw();
    } );
} );
}
</script>
</head>
<body>
<div class="container-fluid">
  <div class="row">
    <div class="col-md-12">
      <button class="btn btn-info" id="btnShow" name="myTaskList">
        My Task List
      </button>
    </div>
  </div>
  <div class="row" style="margin-top:2em">
  <div class="col-md-10" id="myTaskListTable">
      <table class="table display" style="display:none" id="example">
            <thead>
                <tr>
                    <th>Name</th>
                    <th>Pos</th>
                    <th>No</th>
                    <th>Yrs</th>
                    <th>GP</th>
                    <th>Collage</th>
                </tr>
            </thead>
      </table>
    </div>
  </div>
</div>
</body>
</html>


whichrtmej

This question has accepted answers - jump to:

Answers

  • colincolin Posts: 15,240Questions: 1Answers: 2,599
    Answer ✓

    Hi, it's because you are initialising the table twice with different options: lines 45 and 50. Just put the 'dom' on line 51 into the first initialisation

    C

  • whichrtmejwhichrtmej Posts: 3Questions: 1Answers: 0
    edited July 2018

    Works great. Thank you very much.

  • whichrtmejwhichrtmej Posts: 3Questions: 1Answers: 0

    So once the table is displayed and a use selects another table to display, not a DataTable, the DataTable is hidden and the user's new table is shown. If I go back to show my original DataTable it will not show up.

    Do I need to destroy the hidden table then reload it or just reload it? Where would I put the reload/destroy code as I have tried placing it in an else statement as below, which did not work.

    $(document).ready(function(){
      $("#btnShow").click(function(){
          if(! $.fn.DataTable.isDataTable( '#example' )){
            showTable();
          }else {
          var table = $('#example').DataTable({
            table.reload();
          }
      });
    });
    
    
    

    Thanks whichrtmej

  • allanallan Posts: 63,516Questions: 1Answers: 10,472 Site admin
    Answer ✓

    It entirely depends on how you are hiding it. If you are removing it from the DOM, that you could insert it back in (assuming you have a reference to it). If you are just using display:none then display:block should be all that is needed.

    I'd need a link to a test case showing the issue to be able to say more than that. JSFiddle or http://live.datatables.net can be used to create a test case if you can't host it yourself.

    Allan

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