Export: only visible columns when I have others filter to evaluate

Export: only visible columns when I have others filter to evaluate

itajackassitajackass Posts: 165Questions: 49Answers: 3
edited October 2023 in Free community support

Hi, i'd like to export from a table:
-only visible columns
-excluding some columns by class name

Example here:

https://live.datatables.net/lapatino/1/edit

Actually the correct code for me is:

exportOptions: {
columns: function(idx, data, node) {
                            if ( $(node).hasClass('act') ) {
                return false;
            }
            return $("#table_name_i_don_want_to_wrhite_again").DataTable().column(idx).visible();
    }
}

Where I can exclude columns with class "act" (where I have buttons) and then export only visible one. Then problem is that in this case i need to explicit the id of the table inside he return: "table_name_i_don_want_to_wrhite_again"

Because i have a lot of table in differents pages where i need the same export config... when copy/paste it i need to pay attention to replace "table_name_i_don_want_to_wrhite_again" with the name of the correct table.

I'm looking for a way to transform this "exportOptions" universal, so when i do a copy/paste i can do it without the problem of replacing id table name.

I tried so this way but it doesn't work:

exportOptions: {
columns: function(idx, data, node) {
                            if ( $(node).hasClass('act') ) {
                return false;
            }
            return ':visible';
    }
}

Any suggest to "read" the id of the table inside the function(idx, data, node) to get it "reusable" with a simple copy/paste?
Thanks

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